Giải phương trình x + 4/x^2 - 3x + 2 + x + 1/x^2 - 4x + 3 = 2x + 5/x^2 - 4x + 3

x+4x2−3x+2+x+1x2−4x+3=2x+5x2−4x+3⇔x+4x−1x−2=x+4x−1x−3x≠1;2;3

⇒x+4x−1x−3−x+4x−1x−2=0⇔x+4x−1x−3−x+2=0⇔x=−4(tm)x=1(ktm)

Vậy x = -4