Giải phương trình sin^2x + sin^22x = 1.
Giải thích
Ta có:
sin2x + sin22x = 1
⇔1−cos2x2+1−cos22x=1
⇔cos22x+12cos2x−12=0
⇔cos2x=−1cos2x=12⇔2x=π+k2π2x=π3+m2π2x=−π3+n2π⇔x=π2+kπx=π6+mπx=−π6+nπ
Ta có:
sin2x + sin22x = 1
⇔1−cos2x2+1−cos22x=1
⇔cos22x+12cos2x−12=0
⇔cos2x=−1cos2x=12⇔2x=π+k2π2x=π3+m2π2x=−π3+n2π⇔x=π2+kπx=π6+mπx=−π6+nπ