Giải phương trình sau: x-1/ 2015 + x-3 /2013 = x -5 /2011 + x-7 /2009 .

\(\frac{{x - 1}}{{2015}} + \frac{{x - 3}}{{2013}} = \frac{{x - 5}}{{2011}} + \frac{{x - 7}}{{2009}}\)

\(\frac{{x - 1}}{{2015}} - 1 + \frac{{x - 3}}{{2013}} - 1 = \frac{{x - 5}}{{2011}} - 1 + \frac{{x - 7}}{{2009}} - 1\)

\(\frac{{x - 2016}}{{2015}} + \frac{{x - 2016}}{{2013}} = \frac{{x - 2016}}{{2011}} + \frac{{x - 2016}}{{2009}}\)

\(\frac{{x - 2016}}{{2015}} + \frac{{x - 2016}}{{2013}} - \frac{{x - 2016}}{{2011}} - \frac{{x - 2016}}{{2009}} = 0\)

\(\left( {x - 2016} \right)\left( {\frac{1}{{2015}} + \frac{1}{{2013}} - \frac{1}{{2011}} - \frac{1}{{2009}}} \right) = 0\)

Nhận thấy \(\left( {\frac{1}{{2015}} + \frac{1}{{2013}} - \frac{1}{{2011}} - \frac{1}{{2009}}} \right) \ne 0\) nên \(x - 2016 = 0\) suy ra \(x = 2016\).

Vậy \(x = 2016\).