Giải phương trình sau 2/3x + 2 = 1/3

\(\frac{2}{3}x + 2 = \frac{1}{3}\)                            

\(\frac{2}{3}x = \frac{1}{3} - 2\)                                                                             

            \(\frac{2}{3}x = - \frac{5}{3}\)                                                                                     

                \(x = - \frac{5}{2}\)                                                                

Vậy phương trình có nghiệm \(x = - \frac{5}{2}\)