Giải phương trình: d) căn x+4 - căn 1-x = căn 1-2x
Giải thích
d)
x+4−1−x=1−2x⇔x+4=1−2x+1−x
⇔−4≤x≤12x+4=1−x+2(1−x)(1−2x)+1−2x⇔−4≤x≤12(1−x)(1−2x)=2x+1
⇔−4≤x≤12x≥−12(1−x)(1−2x)=4x2+4x+1⇔−12≤x≤12x=0∨x=−72⇔x=0
d)
x+4−1−x=1−2x⇔x+4=1−2x+1−x
⇔−4≤x≤12x+4=1−x+2(1−x)(1−2x)+1−2x⇔−4≤x≤12(1−x)(1−2x)=2x+1
⇔−4≤x≤12x≥−12(1−x)(1−2x)=4x2+4x+1⇔−12≤x≤12x=0∨x=−72⇔x=0