Giải phương trình cos4x/3=cos^2x . A.[x=k3 pi x=+-pi/4+k 3pi +-5pi/+k3 pi
Giải thích
Chọn A
cos4x3=cos2x⇔cos4x3=1+cos2x2⇔2cos2.2x3=1+cos3.2x3
⇔22cos22x3−1=1+4cos32x3−3cos2x3⇔4cos32x3−4cos22x3−3cos2x3+3=0
⇔cos2x3=1cos2x3=±322x3=k2π2x3=±π6+k2π2x3=±5π6+k2π⇔x=k3πx=±π4+k3πx=±5π4+k3π.