Giải phương trình 2x−1/x+3=x+3/2x−1.
Giải thích
\[\begin{array}{l}\frac{{2x - 1}}{x} + 3 = \frac{{x + 3}}{{2x - 1}}\,\,\,\,,dkxd\,\,x \ne 0,x \ne \frac{1}{2}\\\frac{{{{(2x - 1)}^2} + 3x(2x - 1)}}{{x(2x - 1)}} = \frac{{x(x + 3)}}{{x(2x - 1)}}\end{array}\]
\[\begin{array}{l}\\4{x^2} - 4x + 1 + 6{x^2} - 3x - {x^2} - 3x = 0\\9{x^2} - 10x + 1 = 0\\x = 1\,(tm),x = \frac{1}{9}\,(tm)\\KL\end{array}\]