Giải phương trình 1/8x+(5-x)/(4x^2-8x)=(x-1)/2x(x-2)
Giải thích
78x+5−x4x2−8x=x−12xx−2+18x−16x≠0x≠2⇔78x+5−x4xx−2=x−12xx−2+18x−2MTC:8xx−2⇔7x−2+25−x8xx−2=4x−1+x8xx−2⇒7x−14+10−2x=4x−4+x⇔0x=0⇒x∈ℝS=x∈ℝ/x≠0;2
78x+5−x4x2−8x=x−12xx−2+18x−16x≠0x≠2⇔78x+5−x4xx−2=x−12xx−2+18x−2MTC:8xx−2⇔7x−2+25−x8xx−2=4x−1+x8xx−2⇒7x−14+10−2x=4x−4+x⇔0x=0⇒x∈ℝS=x∈ℝ/x≠0;2