Giải các phương trình sau: (9x^2 – 4)(x + 1) = (3x + 2)(x^2 - 1)
Giải thích
(9x2–4)(x+1)=(3x+2)(x2-1)
⇔ (3x – 2)(3x + 2)(x + 1) - (3x + 2)(x - 1)(x + 1) = 0
⇔(3x+ 2)(x + 1)(3x – 2 – x + 1) = 0
⇔ (3x + 2)(x + 1)(2x – 1) = 0
(9x2–4)(x+1)=(3x+2)(x2-1)
⇔ (3x – 2)(3x + 2)(x + 1) - (3x + 2)(x - 1)(x + 1) = 0
⇔(3x+ 2)(x + 1)(3x – 2 – x + 1) = 0
⇔ (3x + 2)(x + 1)(2x – 1) = 0