Giải các phương trình sau: ( 5x^2 - 2x + 10 )^2 = ( 3x^2 + 10x - 8 )^2
Giải thích
Ta có:
(5x2 – 2x + 10)2 = (3x2 + 10x – 8)2
⇔ (5x2 – 2x + 10)2 – (3x2 + 10x – 8)2 = 0
⇔ [(5x2 – 2x + 10) + (3x2 + 10x – 8)] . [(5x2 – 2x + 10) – (3x2 + 10x – 8)] = 0
⇔ (8x2 + 8x + 2)(2x2 – 12x + 18) = 0
⇔ 4(4x2 + 4x + 1)(x2 – 6x + 9) = 0
⇔ 4(2x + 1)2(x – 3)2 = 0
⇔2x+12=0x−32=0⇔2x+1=0x−3=0⇔x=−12x=3
Vậy x∈−12;3.