Giải bất phương trình: a) 5(x−1)+7≤1−3(x+2)
Giải thích
a) \(5\left( {x - 1} \right) + 7 \le 1 - 3\left( {x + 2} \right)\) \(\begin{array}{l}5x + 3x \le 5 - 7 + 1 - 6\\8x \le - 7\end{array}\) \(x \le \frac{{ - 7}}{8}\) | b) \(4\left( {x + 8} \right) - 7\left( {x - 1} \right) < 12\) \(\begin{array}{l} - 3x < - 27\\x > 9\end{array}\)
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c) \(4(x - 1,5) - 1,2 \ge 6x - 1\) \(\begin{array}{l}4x - 6x \ge - 1 + 6 + 1,2\\ - 2x \ge 6,2\\x \le - 3,1\end{array}\) | d) \(1,7 - 3(1 - x) < - (x - 1,9)\) \(\begin{array}{l}3x + x < 1,9 - 1,7 + 3\\4x < 3,2\\x < 0,8\end{array}\) |