(Đúng hay Sai) P(AB)=0,12
Giải thích
c) \(P\left( {AB} \right) + P\left( {A\bar B} \right) = P\left( A \right)\)\( \Rightarrow P\left( {AB} \right) = \frac{1}{{40}}\);Suy ra Sai
c) \(P\left( {AB} \right) + P\left( {A\bar B} \right) = P\left( A \right)\)\( \Rightarrow P\left( {AB} \right) = \frac{1}{{40}}\);Suy ra Sai