Phiếu bài tập hàng ngày Toán lớp 5 Bài 6. Cộng, trừ hai phân số khác mẫu số (có đáp án)

Đúng ghi Đ, sai ghi S.

5/11

Đúng ghi Đ, sai ghi S.

a

\(\frac{3}{4}\,\, + \,\,\frac{8}{9}\,\, = \,\,\frac{{12}}{{36}}\,\, + \,\,\frac{{72}}{{36}}\,\, = \,\,\frac{{84}}{{36}}\,\, = \,\,\frac{7}{3}\)

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b

\(\frac{5}{8}\,\, - \,\,\frac{3}{5}\,\, = \,\,\frac{{25}}{{40}}\,\, - \,\,\frac{{24}}{{40}}\,\, = \,\,\frac{1}{{40}}\)

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c

\(7\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{7}{{12}}\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{6}{{12}}\,\, = \,\,\frac{1}{2}\)

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d

\(\frac{{12}}{7}\,\, + \,\,3\,\, = \,\,\frac{{12}}{7}\,\, + \,\,\frac{{21}}{7}\,\, = \,\,\frac{{33}}{7}\)

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Giải thích

a) \(\frac{3}{4}\,\, + \,\,\frac{8}{9}\,\, = \,\,\frac{{12}}{{36}}\,\, + \,\,\frac{{72}}{{36}}\,\, = \,\,\frac{{84}}{{36}}\,\, = \,\,\frac{7}{3}\)   

Giải thích:

\(\frac{3}{4}\,\, + \,\,\frac{8}{9}\,\, = \,\,\frac{{27}}{{36}}\,\, + \,\,\frac{{32}}{{36}}\,\, = \,\,\frac{{59}}{{36}}\,\,\)

c) \(7\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{7}{{12}}\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{6}{{12}}\,\, = \,\,\frac{1}{2}\)   

Giải thích:

\(7\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{{84}}{{12}}\,\, - \,\,\frac{1}{{12}}\,\, = \,\,\frac{{83}}{{12}}\,\,\)

b)\(\frac{5}{8}\,\, - \,\,\frac{3}{5}\,\, = \,\,\frac{{25}}{{40}}\,\, - \,\,\frac{{24}}{{40}}\,\, = \,\,\frac{1}{{40}}\)           

d) \(\frac{{12}}{7}\,\, + \,\,3\,\, = \,\,\frac{{12}}{7}\,\, + \,\,\frac{{21}}{7}\,\, = \,\,\frac{{33}}{7}\)