Bài tập hàng ngày Toán lớp 5 Kết nối tri thức Bài 5. Ôn tập các phép tính với phân số có đáp án

Đúng ghi Đ, sai ghi S a) \(\frac{{12}}{5}\,\, + \,\,\frac{4}{7}\,\, = \,\,\frac{{104}}{{35}}\)  c) \(\frac{6}{5}\,\,:\,\,\frac{8}{9}\,\, = \,\,\frac{6}{5}\,\, \times \,\,\frac{8}{9}\,\,

5/10

Đúng ghi Đ, sai ghi S

a) \(\frac{{12}}{5}\,\, + \,\,\frac{4}{7}\,\, = \,\,\frac{{104}}{{35}}\) 

c) \(\frac{6}{5}\,\,:\,\,\frac{8}{9}\,\, = \,\,\frac{6}{5}\,\, \times \,\,\frac{8}{9}\,\, = \,\,\frac{{48}}{{45}}\)  

b) \(\frac{1}{2}\,\, + \,\,\frac{3}{2}\,\, \times \,\,\frac{{10}}{7}\,\, = \,\,\frac{4}{2}\,\, \times \,\,\frac{{10}}{7}\,\, = \,\,\frac{{20}}{7}\)  

d) \(\frac{4}{3}\,\, \times \,\,\frac{6}{8}\,\,:\,\,\frac{7}{9}\,\, = \,\,1\,\, \times \,\,\frac{9}{7}\,\, = \,\,\frac{9}{7}\) 

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Giải thích

a) \(\frac{{12}}{5}\,\, + \,\,\frac{4}{7}\,\, = \,\,\frac{{104}}{{35}}\)

Đ

 

Giải thích:

\(\frac{{12}}{5}\,\, + \,\,\frac{4}{7}\,\, = \,\,\frac{{84}}{{35}} + \frac{{20}}{{35}} = \frac{{104}}{{35}}\)

c) \(\frac{6}{5}\,\,:\,\,\frac{8}{9}\,\, = \,\,\frac{6}{5}\,\, \times \,\,\frac{8}{9}\,\, = \,\,\frac{{48}}{{45}}\)

Đ

 

Giải thích:

\(\frac{6}{5}\,\,:\,\,\frac{8}{9}\,\, = \,\,\frac{6}{5}\,\, \times \,\,\frac{9}{8}\,\, = \,\,\frac{{54}}{{40}}\)

b) \(\frac{1}{2}\,\, + \,\,\frac{3}{2}\,\, \times \,\,\frac{{10}}{7}\,\, = \,\,\frac{4}{2}\,\, \times \,\,\frac{{10}}{7}\,\, = \,\,\frac{{20}}{7}\)

Đ

 

Giải thích:

\(\frac{1}{2}\,\, + \,\,\frac{3}{2}\,\, \times \,\,\frac{{10}}{7}\,\, = \,\,\frac{1}{2}\,\, + \,\,\frac{{30}}{{14}}\,\, = \,\,\frac{7}{{14}} + \frac{{30}}{{14}} = \frac{{37}}{{14}}\)

d) \(\frac{4}{3}\,\, \times \,\,\frac{6}{8}\,\,:\,\,\frac{7}{9}\,\, = \,\,1\,\, \times \,\,\frac{9}{7}\,\, = \,\,\frac{9}{7}\)

Đ