Điền >, <, = vào chỗ chấm? 5/8 + 1/4 ... 1/8 + 1/2
6/10
Điền >, <, =?
Điền >, <, =?
a) \[\frac{5}{8} + \frac{1}{4} > \frac{1}{8} + \frac{1}{2}\] c) \[\frac{8}{7} < \frac{2}{3} + \frac{{13}}{{21}}\] | b) \[\frac{3}{4} + \frac{5}{{12}} > \frac{1}{{12}} + \frac{2}{3}\] d) \[\frac{7}{5} + 2 > 1 + \frac{6}{5}\] |
Giải thích
a) \[\frac{5}{8} + \frac{1}{4} = \frac{5}{8} + \frac{2}{8} = \frac{7}{8}\]
\[\frac{1}{8} + \frac{1}{2} = \frac{1}{8} + \frac{4}{8} = \frac{5}{8}\]
So sánh: \[\frac{7}{8} > \frac{5}{8}\] hay \[\frac{5}{8} + \frac{1}{4} > \frac{1}{8} + \frac{1}{2}\]
Vậy dấu cần điền là: >.
b) \[\frac{3}{4} + \frac{5}{{12}} = \frac{9}{{12}} + \frac{5}{{12}} = \frac{{14}}{{12}}\]
\[\frac{1}{{12}} + \frac{2}{3} = \frac{1}{{12}} + \frac{8}{{12}} = \frac{9}{{12}}\]
So sánh: \[\frac{{14}}{{12}} > \frac{9}{{12}}\] hay \[\frac{3}{4} + \frac{5}{{12}} > \frac{1}{{12}} + \frac{2}{3}\]
Vậy dấu cần điền là: >.
c) \[\frac{8}{7} = \frac{{8 \times 3}}{{7 \times 3}} = \frac{{24}}{{21}}\]
\[\frac{2}{3} + \frac{{13}}{{21}} = \frac{{14}}{{21}} + \frac{{13}}{{21}} = \frac{{27}}{{21}}\]
So sánh: \[\frac{{24}}{{21}} < \frac{{27}}{{21}}\] hay \[\frac{8}{7} < \frac{2}{3} + \frac{{13}}{{21}}\]
Vậy dấu cần điền là: <.
d) \[\frac{7}{5} + 2 = \frac{7}{5} + \frac{{10}}{5} = \frac{{17}}{5}\]
\[1 + \frac{6}{5} = \frac{5}{5} + \frac{6}{5} = \frac{{11}}{5}\]
So sánh: \[\frac{{17}}{5} > \frac{{11}}{5}\] hay \[\frac{7}{5} + 2 > 1 + \frac{6}{5}\]
Vậy dấu cần điền là: >.