13 bài tập Đo diện tích – đo thể tích có lời giải
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Điền số thích hợp :

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Điền số thích hợp :

\(9{m^2} = ..........d{m^2}\)

\(490{m^2} = ..........d{m^2}\)

\(172d{m^2} = ..........c{m^2}\)

\(9657d{m^2} = .....{m^2}.....d{m^2}\)

\(9{m^2}3d{m^2} = ..........d{m^2}\)

\(4{m^2}25d{m^2} = ..........c{m^2}\)

\(39d{m^2}4c{m^2} = ..........c{m^2}\)

\(1{m^2}78d{m^2} = ..........c{m^2}\)

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Giải thích

Hướng Dẫn Giải

- \(9{m^2} = ..........d{m^2}\)

\(9{m^2} = 9 \times 100d{m^2} = 900d{m^2}\)

- \(490{m^2} = ..........d{m^2}\)

\(490{m^2} = 490 \times 100d{m^2} = 49000d{m^2}\)

- \(172{\rm{ d}}{{\rm{m}}^2} = ...{\rm{ c}}{{\rm{m}}^2}\)

\(172{\rm{ d}}{{\rm{m}}^2} = 172 \times 100{\rm{ c}}{{\rm{m}}^2} = 17200{\rm{ c}}{{\rm{m}}^2}\).

- \(9657{\rm{d}}{{\rm{m}}^2} = ...{\rm{ }}{{\rm{m}}^2}...{\rm{ d}}{{\rm{m}}^2}\)

\(9657{\rm{ d}}{{\rm{m}}^2} = 9600{\rm{d}}{{\rm{m}}^2} + 57{\rm{d}}{{\rm{m}}^2} = 9600:100{\rm{ }}{{\rm{m}}^2} + 57{\rm{d}}{{\rm{m}}^2} = 96{{\rm{m}}^2} + 57{\rm{d}}{{\rm{m}}^2}\)

\( = 96{{\rm{m}}^2}57{\rm{d}}{{\rm{m}}^2}\)

- \(9{{\rm{m}}^2}3{\rm{d}}{{\rm{m}}^2} = ..........{\rm{d}}{{\rm{m}}^2}\)

\(9{{\rm{m}}^2}3{\rm{d}}{{\rm{m}}^2} = 9{{\rm{m}}^2} + 3{\rm{d}}{{\rm{m}}^2} = 9 \times 100{\rm{d}}{{\rm{m}}^2} + 3{\rm{d}}{{\rm{m}}^2} = 900{\rm{d}}{{\rm{m}}^2} + 3{\rm{d}}{{\rm{m}}^2} = 903{\rm{d}}{{\rm{m}}^2}\)

- \(4{\rm{ }}{{\rm{m}}^2}25{\rm{ d}}{{\rm{m}}^2} = ...{\rm{ c}}{{\rm{m}}^2}\)

\(4{{\rm{m}}^2}25{\rm{d}}{{\rm{m}}^2} = 4{{\rm{m}}^2} + 25{\rm{d}}{{\rm{m}}^2} = 4 \times 10000{\rm{c}}{{\rm{m}}^2} + 25 \times 100{\rm{c}}{{\rm{m}}^2}\)

\( = 40000{\rm{c}}{{\rm{m}}^2} + 2500{\rm{c}}{{\rm{m}}^2} = 42500{\rm{c}}{{\rm{m}}^2}\)

- \(39{\rm{d}}{{\rm{m}}^2}4{\rm{ c}}{{\rm{m}}^2} = ...{\rm{c}}{{\rm{m}}^2}\)

\(39{\rm{d}}{{\rm{m}}^2}4{\rm{c}}{{\rm{m}}^2} = 39{\rm{d}}{{\rm{m}}^2} + 4{\rm{c}}{{\rm{m}}^2} = 39 \times 100{\rm{ c}}{{\rm{m}}^2} + 4{\rm{c}}{{\rm{m}}^2}\)

\( = 3900{\rm{c}}{{\rm{m}}^2} + 4{\rm{c}}{{\rm{m}}^2} = 3904{\rm{c}}{{\rm{m}}^2}\)

- \(1{{\rm{m}}^2}78{\rm{ d}}{{\rm{m}}^2} = ...{\rm{ c}}{{\rm{m}}^2}\)

\(1{{\rm{m}}^2}78{\rm{d}}{{\rm{m}}^2} = 1{{\rm{m}}^2} + 78{\rm{d}}{{\rm{m}}^2} = 1 \times 10000{\rm{c}}{{\rm{m}}^2} + 78 \times 100{\rm{c}}{{\rm{m}}^2}\)

\( = 10000{\rm{c}}{{\rm{m}}^2} + 7800{\rm{c}}{{\rm{m}}^2} = 17800{\rm{c}}{{\rm{m}}^2}\)