Điền dấu >, <, = thích hợp vào chỗ chấm
Giải thích
a) \(\frac{5}{6} + \frac{2}{3}\) > \(\frac{3}{2} - \frac{1}{3}\) | b) \(\frac{2}{3} \times \frac{3}{7}\) < \(\frac{4}{3}:\frac{7}{3}\) |
Giải thích: \(\frac{5}{6} + \frac{2}{3}\) = \(\,\frac{3}{2} = \frac{9}{6}\) \(\frac{3}{2} - \frac{1}{3}\) = \(\frac{7}{6}\,\) \(\frac{9}{6}\,\,\)> \(\frac{7}{6}\) Vậy: \(\frac{5}{6} + \frac{2}{3}\) > \(\frac{3}{2} - \frac{1}{3}\) | Giải thích: \(\frac{2}{3} \times \frac{3}{7}\) = \(\frac{2}{7}\,\,\) \(\frac{4}{3}:\frac{7}{3}\) = \(\frac{4}{7}\,\,\) \(\frac{2}{7}\) < \(\frac{4}{7}\)\(\frac{4}{3}:\frac{7}{3}\) Vậy: \(\frac{2}{3} \times \frac{3}{7}\) < \(\frac{4}{3}:\frac{7}{3}\) |