Đâu là công thức biểu diễn tín hiệu dưới dạng modul và argument

$X\left(e{}^{j\omega }\right)=\text{R}\text{e}\left[X\left(e{}^{j\omega }\right)\right]+j\text{I}\text{m}\left[X\left(e{}^{j\omega }\right)\right]$

$X\left(e{}^{j\omega }\right)=\mid X\left(e{}^{j\omega }\right)e{}^{j\text{a}\text{r}\text{g}\left|X\left(e{}^{j\omega }\right)\right|}$

$X{}_R\left(t\right)=\frac{1}{2}\left[X\left(t\right)+X{}^{\text{*}}\left(t\right)\right]=\frac{1}{2}\left[A\cdot e{}^{j\left(\omega {}_{0}t+q{}_0\right)}+A\cdot e{}^{-j\left(\omega {}_{0}t+q{}_0\right)}\right]$$X{}_I\left(t\right)=\frac{1}{2}\left[X\left(t\right)-X{}^{\text{*}}\left(t\right)\right]=\frac{1}{2}\left[A\cdot e{}^{j\left(\omega {}_{0}t+\phi {}_0\right)}-A\cdot e{}^{-j\left(\omega {}_{0}t+\phi {}_0\right)}\right]$

$X\left(e{}^{j\omega }\right)=A\left(e{}^{j\omega }\right)\cdot e{}^{j\theta \left(\omega \right)}$