Cộng, trừ các phân thức sau: x^3 + x^2 -2x-20/x^2 -4 -5/x+2 + 3/x-2
Giải thích
x3+x2−2x−20x2−4−5x+2+3x−2=x3+x2−2x−20−5x−2+3x+2x−2x+2=x3+x2−4x−4x−2x+2=x+1x2−4x2−4=x+1
x3+x2−2x−20x2−4−5x+2+3x−2=x3+x2−2x−20−5x−2+3x+2x−2x+2=x3+x2−4x−4x−2x+2=x+1x2−4x2−4=x+1