Cộng các phân thức sau: 4/x+2 + 2/x-2 + 5x-6/4-x^2
Giải thích
4x+2+2x−2+5x−64−x2=4x+2+2x−2+6−5xx−2x+2=4x−2+2x+2+6−5xx−2x+2=4x−8+2x+4+6−5xx−2x+2=x+2x−2x+2=1x−2
4x+2+2x−2+5x−64−x2=4x+2+2x−2+6−5xx−2x+2=4x−2+2x+2+6−5xx−2x+2=4x−8+2x+4+6−5xx−2x+2=x+2x−2x+2=1x−2