Chứng minh rằng: (a + b + c)^3 = a^3 + b^3 + c^3 + 3(a + b).(b + c).(c + a).
Giải thích
(a+b+c)3
=(a+b)3+3(a+b)2.c+3.(a+b).c2+c3
=a3+3a2b+3ab2+b3+3(a+b)2.c+3.(a+b).c2+c3
=a3+b3+c3+[3a2b+3ab2+3(a+b)2.c+3.(a+b).c2]
=a3+b3+c3+[3ab(a+b)+3(a+b)2c+3(a+b)c2]
=a3+b3+c3+3(a+b)[ab+(a+b)c+c2]
=a3+b3+c3+3(a+b)(ab+ac+bc+c2)
=a3+b3+c3+3(a+b)[a.(b+c)+c.(b+c)]
=a3+b3+c3+3(a+b)(b+c)(a+c).