Cho A = 4.{3^2.[(52 + 2^3):11] − 26} + 2002 và B = 134 − {150:5 − [120:4 + 25

A = 4.{3².[(5² + 2³):11] − 26} + 2002 

= 4.{3².[(25 + 8):11] − 26} + 2002

= 4.[3².(33:11) − 26] + 2002

= 4.(3².3 − 26) + 2002

= 4.(27 − 26) + 2002

= 4.1 + 2002

= 4 + 2002

=2006.

Và  B = 134 − {150:5 − [120:4 + 25 − (12 + 18)]}

= 134 − [150:5 − (120:4 + 25 − 30)]

= 134 − [150:5 − (30 + 25 − 30)]

= 134 − (150:5 − 25)

= 134 − (30 − 25)

= 134 − 5

= 129

Vậy A = 2006 và B = 129 nên A >B.

Đáp án cần chọn là: D