Cho ma trận A có nghịch đảo, tìm ma trận X thỏa mãn AX−2B=

\[{\rm{A}}{\rm{. }}X = \left( {\begin{array}{*{20}{c}}{21/50}&{3/10}\\{[2mm] - 3/25}&{ - 4/5}\end{array}} \right)\]

\[{\rm{B}}{\rm{. }}X = \left( {\begin{array}{*{20}{c}}{11/50}&{21/25}\\{[1mm]1/5}&{ - 3/5}\end{array}} \right)\]

\[{\rm{C}}{\rm{. }}X = \left( {\begin{array}{*{20}{c}}{3/10}&{21/50}\\{[1mm] - 3/25}&{ - 4/5}\end{array}} \right)\]

\[{\rm{D}}{\rm{. }}X = \left( {\begin{array}{*{20}{c}}{11/50}&{1/52}\\{[1mm]21/25}&{ - 3/5}\end{array}} \right)\]