Cho hàm số \(y = \sin 2x\). Tính \({y^{(n)}}\)

\({y^{(n)}} = {2^n}\sin (2x + n\frac{\pi }{3})\)

\({y^{(n)}} = {2^n}\sin (2x + \frac{\pi }{2})\)

\({y^{(n)}} = {2^n}\sin (x + \frac{\pi }{2})\)

\({y^{(n)}} = {2^n}\sin (2x + n\frac{\pi }{2})\)