Cho hàm số y= f(x) = −x2 + 1. Tính f(−3); f(−2); f(−1); f(0); f(1).
Giải thích
•f(−3) = −(−3)2 + 1= −8
•f(−2) = −(−2)2 + 1 = −3
•f(−1) = −(−1)2 + 1 = 0
•f(0) = −(0)2 + 1 = 1
•f(1) = −(1)2 + 1 = 0
•f(−3) = −(−3)2 + 1= −8
•f(−2) = −(−2)2 + 1 = −3
•f(−1) = −(−1)2 + 1 = 0
•f(0) = −(0)2 + 1 = 1
•f(1) = −(1)2 + 1 = 0