Cho hàm số y=cos3x.sin2x. tính y'(pi/3) bằng
Giải thích
Chọn B
y'=cos3x'sin2x+cos3xsin2x'=−3sin3x.sin2x+2cos3x.cos2x
y'π3=−3sin3π3.sin2π3+2cos3π3.cos2π3=−3.0.32+2.(−1).−12= 1
Chọn B
y'=cos3x'sin2x+cos3xsin2x'=−3sin3x.sin2x+2cos3x.cos2x
y'π3=−3sin3π3.sin2π3+2cos3π3.cos2π3=−3.0.32+2.(−1).−12= 1