Cho hàm số f(x) = sin x. Tính lim h tới 0 f ( x +h) - f(x) /h
Giải thích
Ta có: \(\mathop {\lim }\limits_{h \to 0} \frac{{\sin \left( {x + h} \right) - \sin x}}{h} = \mathop {\lim }\limits_{h \to 0} \frac{{2\cos \left( {x + \frac{h}{2}} \right)\sin \frac{h}{2}}}{h} = \mathop {\lim }\limits_{h \to 0} \frac{{\sin \frac{h}{2}}}{{\frac{h}{2}}}\cos \left( {x + \frac{h}{2}} \right) = 1.\cos x = \cos x\)
Vì:\(\mathop {\lim }\limits_{h \to 0} \frac{{\sin \frac{h}{2}}}{{\frac{h}{2}}} = 1\).