Cho hai đa thức: A(x)=x^6-x^3+2x^4+5x^5+2x^3-x+2x^2+3
Giải thích
Ax=x6−x3+2x4+5x5+2x3−x+2x2+3
=x6+5x5+2x4+−x3+2x3+2x2−x+3
=x6+5x5+2x4+x3+2x2−x+3
Bx=−4x5−x6+3x3+2x−12+3x2−x3
=−x6−4x5+3x3−x3+3x2+2x−12
=−x6−4x5+2x3+3x2+2x−12
Ax=x6−x3+2x4+5x5+2x3−x+2x2+3
=x6+5x5+2x4+−x3+2x3+2x2−x+3
=x6+5x5+2x4+x3+2x2−x+3
Bx=−4x5−x6+3x3+2x−12+3x2−x3
=−x6−4x5+3x3−x3+3x2+2x−12
=−x6−4x5+2x3+3x2+2x−12