Cho hai đa thức A=10x^2y−2/3x^2yz−6xy^2z và B=−xy^2z+5/3x^2yz−29x^2y+2024. Tính A+B.

\(A + B = \left( {10{x^2}y - \frac{2}{3}{x^2}yz - 6x{y^2}z} \right) + \left( { - x{y^2}z + \frac{5}{3}{x^2}yz - 29{x^2}y + 2024} \right)\) \(\begin{array}{*{20}{r}}{}&{}\\{}&{}\\{}&{}\end{array}\)

\( = 10{x^2}y - \frac{2}{3}{x^2}yz - 6x{y^2}z - x{y^2}z + \frac{5}{3}{x^2}yz - 29{x^2}y + 2024\)

\( = \left( {10{x^2}y - 29{x^2}y} \right) + \left( { - \frac{2}{3}{x^2}yz + \frac{5}{3}{x^2}yz} \right) + \left( { - 6x{y^2}z - x{y^2}z} \right) + 2024\)

\( = - 19{x^2}y + {x^2}yz - 7x{y^2}z + 2024\)