Cho hai biểu thức: A = 2 + căn bậc hai x / căn bậc hai x

\(1.\,A = \frac{{2 + \sqrt x }}{{\sqrt x }} = \frac{{2 + \sqrt {64} }}{{\sqrt {64} }} = \frac{5}{4}\)

\(2.\,B = \frac{{\sqrt x  - 1}}{{\sqrt x }} + \frac{{2\sqrt x  + 1}}{{x + \sqrt x }} = \frac{{\left( {\sqrt x  - 1} \right)\left( {\sqrt x  + 1} \right)}}{{\sqrt x \left( {\sqrt x  + 1} \right)}} + \frac{{2\sqrt x  + 1}}{{\sqrt x \left( {\sqrt x  + 1} \right)}}\)

\( = \frac{{\sqrt x  + 2}}{{\sqrt x  + 1}}\)

\(3.\,\,\frac{{\sqrt x  + 2}}{{\sqrt x }}:\frac{{\sqrt x  + 2}}{{\sqrt x  + 1}} > \frac{3}{2} \Leftrightarrow \frac{{\sqrt x  + 1}}{{\sqrt x }} > \frac{3}{2}\)

\( \Leftrightarrow 0 < x < 4\)