Cho góc alpha thỏa mãn tan alpha  = 15

ChọnC.    Ta có:\(P = \frac{{3\sin \alpha + 2\cos \alpha }}{{5\cos \alpha - \sin \alpha }} = \frac{{3\frac{{\sin \alpha }}{{\cos \alpha }} + 2}}{{5 - \frac{{\sin \alpha }}{{\cos \alpha }}}} = \frac{{3\tan \alpha . + 2}}{{5 - \tan \alpha }} = \frac{{3.15 + 2}}{{5 - 15}} = - \frac{{47}}{{10}}.\)