Cho \(\cos \alpha = \frac{1}{3}\). Khi đó \(\sin \left( {\alpha - \frac{{3\pi }}{2}} \right)\) bằng

Ta có \(\sin \left( {\alpha - \frac{{3\pi }}{2}} \right) = \sin \alpha \cos \frac{{3\pi }}{2} - \cos \alpha \sin \frac{{3\pi }}{2} = \sin \alpha \cdot 0 - \frac{1}{3} \cdot \left( { - 1} \right) = \frac{1}{3}\). Chọn D.