Cho các đa thức: B(x)=3x-5+4x^3-8x+10 C(x)=-3x^2+5-8x+2x^4+x^3-4
Giải thích
Bx=3x−5+4x3−8x+10=4x3+3x−8x+10−5=4x3−5x+5
Cx=−3x2+5−8x+2x4+x3−4=2x4+x3−3x2−8x+5−4=2x4+x3−3x2−8x+1
Bx=3x−5+4x3−8x+10=4x3+3x−8x+10−5=4x3−5x+5
Cx=−3x2+5−8x+2x4+x3−4=2x4+x3−3x2−8x+5−4=2x4+x3−3x2−8x+1