Cho các đa thức A = 5x^2 - 2xy + 3xy^2,

Ta có \(A + B - C = \left( {5{x^2} - 2xy + 3x{y^2}} \right) + \left( { - 2{x^2} - 2x{y^2} + xy} \right) - \left( {{x^2} - 3{x^2}y + xy - 2{x^3}} \right)\)

                  \( = 5{x^2} - 2xy + 3x{y^2} - 2{x^2} - 2x{y^2} + xy - {x^2} + 3{x^2}y - xy + 2{x^3}\)

                  \( = 2{x^3} + \left( {5{x^2} - 2{x^2} - {x^2}} \right) + \left( { - 2xy + xy - xy} \right) + \left( {3x{y^2} - 2x{y^2}} \right) + 3{x^2}y\)

                  \( = 2{x^3} + 2{x^2} - 2xy + x{y^2} + 3{x^2}y\).

\(A - 2B + C = \left( {5{x^2} - 2xy + 3x{y^2}} \right) - 2\left( { - 2{x^2} - 2x{y^2} + xy} \right) + \left( {{x^2} - 3{x^2}y + xy - 2{x^3}} \right)\)

                  \( = 5{x^2} - 2xy + 3x{y^2} + 4{x^2} + 4x{y^2} - 2xy + {x^2} - 3{x^2}y + xy - 2{x^3}\)

                  \( =  - 2{x^3} + \left( {5{x^2} + 4{x^2} + {x^2}} \right) + \left( { - 2xy - 2xy + xy} \right) + \left( {3x{y^2} + 4x{y^2}} \right) - 3{x^2}y\)

                  \( =  - 2{x^3} + 10{x^2} - 3xy + 7x{y^2} - 3{x^2}y\).