Cho a = -6, b = 3, c = -2. Tính: |a + b − c|; |a – b + c|; |a – b − c|
Giải thích
|a + b − c| = |−6 + 3 − (−2)| = |−6 + 3 + 2 | = |−1| = 1;
|a – b + c| = |−6 – 3 + (−2)| = |−6 – 3 − 2| = |−11| = 11;
|a – b – c| = |−6 – 3 − (−2)| = |−6 – 3 + 2| = |−7| = 7.