Cho 1 ∫ 0 f ( x ) d x = 2 và 1 ∫ 0 g ( x ) dx = 5 , khi 1 ∫ 0 [ f ( x ) − 2 g ( x ) ] dx bằng:

20/49

Cho \(\int\limits_0^1 {f\left( x \right){\rm{d}}x} = 2{\mkern 1mu} \) và \(\int\limits_0^1 {g\left( x \right){\rm{d}}x} = 5{\mkern 1mu} \), khi \(\int\limits_0^1 {\left[ {f\left( x \right) - 2g\left( x \right)} \right]{\rm{d}}x} {\mkern 1mu} \) bằng:

\( - 8\).

\(1\).

\( - 3\).

\(12\).

Giải thích

Có \(\int\limits_0^1 {\left[ {f\left( x \right) - 2g\left( x \right)} \right]{\rm{d}}x} = \int\limits_0^1 {f\left( x \right){\rm{d}}x} - 2\int\limits_0^1 {g\left( x \right){\rm{d}}x} \)\( = 2 - 2 \cdot 5 = - 8\). ChọnA.