Câu 3. Cho \(\int {f\left( x \right){\rm{d}}x} = {F_1}\left( x \right)\), \(\int {g\left( x \right){\rm{d}}x} = {F_2}\left( x \right)\). Tính \[I = \int {\left[ {2g\left( x \right) - f\left

3/11

Cho \(\int {f\left( x \right){\rm{d}}x} = {F_1}\left( x \right)\), \(\int {g\left( x \right){\rm{d}}x} = {F_2}\left( x \right)\). Tính \[I = \int {\left[ {2g\left( x \right) - f\left( x \right)} \right]{\rm{d}}x} \].

\(2{F_1}\left( x \right) - {F_2}\left( x \right) + C\).

\({F_2}\left( x \right) - {F_1}\left( x \right) + C\).

\(2{F_2}\left( x \right) - {F_1}\left( x \right) + C\).

\(\left| {{F_1}\left( x \right) + {F_2}\left( x \right)} \right| + C\).

Giải thích

Chọn đáp án C

Do \[I = \int {\left[ {2g\left( x \right) - f\left( x \right)} \right]{\rm{d}}x} = 2\int {g\left( x \right)} {\rm{d}}x - \int {f\left( x \right)} {\rm{d}}x = 2{F_2}\left( x \right) - {F_1}\left( x \right) + C\].