c) ∀ α ∈ ( 0 ; + ∞ ) , ∫ x ^ α d x = x ^ α + 1 / α − 1 + C .

c) \(\forall \alpha \in (0; + \infty ),\int {{x^\alpha }} dx = \frac{{{x^{\alpha + 1}}}}{{\alpha + 1}} + C.\)

=> Sai