Biết lim căn {3x + 1} - 1 / x} = a/b
Giải thích
Chọn D
Ta có: \[\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt {3x + 1} - 1}}{x} = \mathop {\lim }\limits_{x \to 0} \frac{{(\sqrt {3x + 1} - 1)(\sqrt {3x + 1} + 1)}}{{x(\sqrt {3x + 1} + 1)}} = \mathop {\lim }\limits_{x \to 0} \frac{{3x}}{{x(\sqrt {3x + 1} + 1)}} = \mathop {\lim }\limits_{x \to 0} \frac{3}{{\sqrt {3x + 1} + 1}} = \frac{3}{2} = \frac{a}{b}\]
Vậy \(P = {a^2} + {b^2} = {3^2} + {2^2} = 13\)