b. x/x-2 + x-2/x > 2

b)xx−2+x−2x>2⇔x2x(x−2)+x−22x(x−2)−2xx−2xx−2>0⇔x2+x2−4x+4−2x2+4xxx−2>0⇔4xx−2>0⇔xx−2>0⇔x>0x−2>0x<0x−2<0⇔x>0x>2x<0x<2⇔x>2x<0

Vậy x>2x<0