b. x-5/27 + x-4/28 + x-3/29 + x-2/30 < 4
Giải thích
b)x−527+x−428+x−329+x−230<4⇔x−3227+x−3228+x−3229+x−3230<0⇔x−32127+128+129+130<0⇔x−32<0⇔x<32
Vậy x < 32
b)x−527+x−428+x−329+x−230<4⇔x−3227+x−3228+x−3229+x−3230<0⇔x−32127+128+129+130<0⇔x−32<0⇔x<32
Vậy x < 32