B. TỰ LUẬN (3,0 điểm)Câu25-26. (1,5 điểm)
1) a) \(\frac{2}{7} + \frac{5}{7} \cdot \left( {60\% - 0,25} \right) \cdot {\left( { - 2} \right)^2}\) \( = \frac{2}{7} + \frac{5}{7} \cdot \left( {\frac{{60}}{{100}} - \frac{{25}}{{100}}} \right) \cdot 4\) \( = \frac{2}{7} + \frac{5}{7} \cdot 4 \cdot \frac{{35}}{{100}}\) \( = \frac{2}{7} + \frac{{20}}{7}.\frac{7}{{20}}\) \[ = \frac{2}{7} + 1\]\[ = \frac{9}{7}\].
| b) \(\frac{2}{5} \cdot \left( {\frac{{ - 5}}{{12}} + \frac{{ - 9}}{{13}}} \right) - \frac{2}{5} \cdot \left( {\frac{8}{{13}} - \frac{5}{{12}}} \right):2\) \( = \frac{1}{5} \cdot 2 \cdot \left( {\frac{{ - 5}}{{12}} + \frac{{ - 9}}{{13}}} \right) - \frac{2}{5} \cdot \left( {\frac{8}{{13}} - \frac{5}{{12}}} \right) \cdot \frac{1}{2}\) \( = \frac{1}{5} \cdot \left( {\frac{{ - 10}}{{12}} + \frac{{ - 18}}{{13}}} \right) - \frac{1}{5} \cdot \left( {\frac{8}{{13}} - \frac{5}{{12}}} \right)\) \[ = \frac{1}{5} \cdot \left( {\frac{{ - 10}}{{12}} + \frac{{ - 18}}{{13}} - \frac{8}{{13}} + \frac{5}{{12}}} \right)\] \[ = \frac{1}{5} \cdot \left[ {\left( {\frac{{ - 10}}{{12}} + \frac{5}{{12}}} \right) + \left( {\frac{{ - 18}}{{13}} - \frac{8}{{13}}} \right)} \right]\] \[ = \frac{1}{5} \cdot \left( {\frac{{ - 5}}{{12}} + \frac{{ - 26}}{{13}}} \right) = \frac{1}{5} \cdot \left[ {\frac{{ - 5}}{{12}} + \left( { - 2} \right)} \right]\] \[ = \frac{1}{5} \cdot \frac{{ - 29}}{{12}} = \frac{{ - 29}}{{60}}.\] |