B. TỰ LUẬN (3,0 điểm)
Hướng dẫn giải
a) \(\frac{{ - 5}}{{12}} + \frac{4}{{37}} + \frac{{17}}{{12}} - \frac{{41}}{{37}}\) \( = \left( {\frac{{ - 5}}{{12}} + \frac{{17}}{{12}}} \right) + \left( {\frac{4}{{37}} - \frac{{41}}{{37}}} \right)\) \( = \frac{{12}}{{12}} + \left( { - \frac{{37}}{{37}}} \right)\) \( = 1 + \left( { - 1} \right)\) \( = 0.\) | b) \({\left( { - \frac{1}{2}} \right)^2}.4 + \frac{1}{3}{.3^2} + {\left( {\frac{1}{{1\,\,000}}} \right)^0}\) \( = \frac{1}{4}.4 + \frac{1}{3}.9 + 1\) \( = 1 + 3 + 1\) \( = 5\). | c) \(\left( {\frac{7}{5} + \frac{1}{{11}} - \left| { - 1,2} \right|} \right) - \left( {\sqrt {\frac{1}{{121}}} + 0,8 + \frac{2}{5}} \right)\) \( = \left( {\frac{7}{5} + \frac{1}{{11}} - 1,2} \right) - \left( {\sqrt {{{\left( {\frac{1}{{11}}} \right)}^2}} + 0,8 + \frac{2}{5}} \right)\) \( = \left( {\frac{7}{5} + \frac{1}{{11}} - 1,2} \right) - \left( {\frac{1}{{11}} + 0,8 + \frac{2}{5}} \right)\) \( = \frac{7}{5} + \frac{1}{{11}} - 1,2 - \frac{1}{{11}} - 0,8 - \frac{2}{5}\) \( = \left( {\frac{7}{5} - \frac{2}{5}} \right) + \left( {\frac{1}{{11}} - \frac{1}{{11}}} \right) + \left( { - 1,2 - 0,8} \right)\) \( = 1 + 0 + \left( { - 2} \right) = - 1.\) |