) ∫ b 5 | x − 5 | d x = ∫ b 5 ( x − 5 ) d x = ( x 2 2 − 5 x ) ∣ ∣ b 5 = ( b 2 2 − 5 b ) + 25 2

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c) \(\int_5^b | x - 5|dx = \int_5^b {(x - 5)} dx = \left. {\left( {\frac{{{{\rm{x}}^2}}}{2} - 5{\rm{x}}} \right)} \right|_5^{\rm{b}} = \left( {\frac{{{{\rm{b}}^2}}}{2} - 5\;{\rm{b}}} \right) + \frac{{25}}{2}\)

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Giải thích

c) \(\int_5^{\rm{b}} | {\rm{x}} - 5|{\rm{dx}} = \int_5^{\rm{b}} {({\rm{x}} - 5)} {\rm{dx}} = \left. {\left( {\frac{{{{\rm{x}}^2}}}{2} - 5{\rm{x}}} \right)} \right|_5^{\rm{b}} = \left( {\frac{{{{\rm{b}}^2}}}{2} - 5\;{\rm{b}}} \right) + \frac{{25}}{2}\)

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