b= (-2)^24. 3^5-4^12

Lời giải:

\[\frac{{{{( - 2)}^{24}}{{.3}^5} - {4^{12}}{{.9}^2}}}{{{8^8}{{.3}^5}}} + \frac{2}{{1.3}} + \frac{2}{{3.5}} + \frac{2}{{5.7}} + ... + \frac{2}{{301.303}}\]

= \[\frac{{{2^{24}}{{.3}^5} - {2^{24}}{{.3}^4}}}{{{2^{24}}{{.3}^5}}} + 1 - \frac{1}{3} + \frac{1}{3} - \frac{1}{5} + ... + \frac{1}{{301}} - \frac{1}{{303}}\]

= \[\frac{{{2^{24}}{{.3}^4}.(3 - 1)}}{{{2^{24}}{{.3}^5}}} + \frac{{302}}{{303}}\]= \[\frac{2}{3} + \frac{{302}}{{303}}\]

= \[\frac{{168}}{{101}}\]