27x^3 27x^2 9x 1-(1 3x)^4 phan tich nhan tu
Giải thích
\[27{x^3} + 27{x^2} + 9x + 1 + x + \frac{1}{3}\]
\[ = {\left( {3x + 1} \right)^3} + \frac{1}{3}\left( {3x + 1} \right)\]
\[ = \left( {3x + 1} \right)\left[ {{{\left( {3x + 1} \right)}^2} + \frac{1}{3}} \right]\]
\[ = \left( {3x + 1} \right)\left( {9{x^2} + 6x + \frac{4}{3}} \right).\]