- 25{n^5} + 2{n^2} - căn 3 / n- 3{n^3} + 5{n^5 bằng:

Chọn B

\(\lim \frac{{ - 25{n^5} + 2{n^2} - \sqrt 3 }}{{n - 3{n^3} + 5{n^5}}} = \lim \frac{{ - 25 + \frac{2}{{{n^3}}} - \frac{{\sqrt 3 }}{{{n^5}}}}}{{\frac{1}{{{n^4}}} - \frac{3}{{{n^2}}} + 5}} = - 5\).