Giải SBT Toán 7 Bài tập cuối chương 1 có đáp án

- 2^15; 9^4/6^6; 8^3 + 0,75; - 1/2 + 0,375

15/25

\( - \frac{{{2^{15}}\,\,.\,\,{9^4}}}{{{6^6}\,\,.\,\,{8^3}}} + 0,75\,\,.\,\,\frac{{ - 1}}{2} + 0,375\).

0/3000 ký tự
Giải thích

Lời giải:

\( - \frac{{{2^{15}}\,\,.\,\,{9^4}}}{{{6^6}\,\,.\,\,{8^3}}} + 0,75\,\,.\,\,\frac{{ - 1}}{2} + 0,375\)

\( = - \frac{{{2^{15}}\,\,.\,\,{{\left( {{3^2}} \right)}^4}}}{{{{(2\,.\,3)}^6}\,\,.\,\,{{\left( {{2^3}} \right)}^3}}} + ( - 0,375) + 0,375\)

\( = - \frac{{{2^{15}}\,\,.\,\,{3^8}}}{{{2^6}\,.\,{3^6}\,\,.\,\,{2^9}}} + [( - 0,375) + 0,375]\)

\( = - \frac{{{2^{15}}\,\,.\,\,{3^8}}}{{{2^6}\,.\,{3^6}\,\,.\,\,{2^9}}} + [( - 0,375) + 0,375]\)

\( = - \frac{{{3^8}}}{{{3^6}}} = - {3^2} = - 9\).