(2,0 điểm) Tính giá trị của các biểu thức sau (tính hợp lí nếu có thể):
a) \(\frac{{ - 3}}{4} + \frac{1}{4}:\frac{2}{3} = \frac{{ - 3}}{4} + \frac{1}{4}.\frac{3}{2} = \frac{{ - 3}}{4} + \frac{3}{8} = \frac{{ - 6}}{8} + \frac{3}{8} = \frac{{ - 3}}{8}\);
b) \({\left( {\frac{2}{7}} \right)^{10}}{.7^{10}} = \frac{{{2^{10}}}}{{{7^{10}}}}{.7^{10}} = {2^{10}} = 1\,024\);
c) \(\sqrt {\frac{{25}}{{16}}} - \left| { - \frac{2}{3}} \right| = \frac{5}{4} - \frac{2}{3} = \frac{{15}}{{12}} - \frac{8}{{12}} = \frac{7}{{12}}\);
d) \(\left( {\frac{1}{3} - \frac{3}{{10}}} \right):\frac{3}{5} + \left( {\frac{2}{3} - \frac{7}{{10}}} \right):\frac{3}{5} = \left( {\frac{1}{3} - \frac{3}{{10}}} \right).\frac{5}{3} + \left( {\frac{2}{3} - \frac{7}{{10}}} \right).\frac{5}{3}\)
\( = \left( {\frac{1}{3} - \frac{3}{{10}} + \frac{2}{3} - \frac{7}{{10}}} \right).\frac{5}{3} = \left( {1 - 1} \right).\frac{5}{3} = 0\).