9 câu Trắc nghiệm Toán 9 Bài 9: Căn bậc ba có đáp án (Nhận biết)

$\sqrt[3]{a^3}=2x\iff$ a³ = 2x

$\sqrt[3]{a^3}=2x\iff$ 2a = x³

$\sqrt[3]{a^3}=2x\iff$ a = 2x³

$\sqrt[3]{a^3}=2x\iff$ a = 8x³

$\sqrt[3]{a}>\sqrt[3]{b}\iff$ a > b

$\sqrt[3]{a}>\sqrt[3]{b}\iff$ a < b

$\sqrt[3]{a}\ge \sqrt[3]{b}\iff$ a = b

$\sqrt[3]{a}<\sqrt[3]{b}\iff$ a > b

a > b $\iff \sqrt[3]{a}>\sqrt[3]{b}$

a < b $\iff \sqrt[3]{a}<\sqrt[3]{b}$

$a\ge b\iff \sqrt[3]{a}\ge \sqrt[3]{b}$

a < b $\iff \sqrt[3]{a}>\sqrt[3]{b}$

$\sqrt[3]{a}.\sqrt[3]{b}=\sqrt[3]{ab}$

$\sqrt[3]{\frac{a}{b}}=\frac{\sqrt[3]{a}}{\sqrt[3]{b}}$ với b $\ne$0

${\left(\sqrt[3]{a}\right)}^3=a$

$\sqrt[3]{a^3}=\left|a\right|$

$\sqrt[3]{ab}=\sqrt{a}.\sqrt{b}$

$\frac{\sqrt[3]{a}}{\sqrt[3]{b}}=\frac{a}{b}$ với b $\ne$ 0

$\sqrt[3]{a}$ = −a khi a < 0

$\frac{\sqrt[3]{a}}{\sqrt[3]{b}}=\sqrt[3]{\frac{a}{b}}$ với b $\ne$ 0

$\sqrt[3]{27}=9$

$\sqrt[3]{27}=3$

$\sqrt[3]{27}=-3$

$\sqrt[3]{27}=-9$

$\sqrt[3]{-125}$ = −25

$\sqrt[3]{-125}$ = −5

$\sqrt[3]{-125}$ = 25

$\sqrt[3]{-125}$ = 5

$\sqrt[3]{-\frac{1}{8a^3}}=-\frac{1}{2a}$

$\sqrt[3]{-\frac{1}{8a^3}}=\frac{1}{2a}$

$\sqrt[3]{-\frac{1}{8a^3}}=\frac{1}{4a}$

$\sqrt[3]{-\frac{1}{8a^3}}=-\frac{1}{2a^2}$